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The energy of electron in an excited hyd...

The energy of electron in an excited hydrogen atom is `-3.4eV`. Its angular momentum according to bohr's theory will be

A

`(h)/(pi)`

B

`(h)/(2pi)`

C

`(3h)/(2pi)`

D

`(3)/(2pih)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(n) =-(13.6)/(n^2)=-3.4rArr n=2,L=(nh)/(2pi)=h//pi`
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