Home
Class 12
PHYSICS
The de broglie wavelength of an electron...

The de broglie wavelength of an electron in the first Bohr orbit is equal to

A

Equal to the circumference of the first orbit

B

1/2 th circumference of the first orbit

C

1/4 th circumference of the first orbit

D

3/4 th circumference of the first orbit

Text Solution

Verified by Experts

The correct Answer is:
A
` mvr = (nh)/(2pi), 2pi gamma = (h)/(mv) , 2 pi r = lambda`.
Promotional Banner

Topper's Solved these Questions

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (C.W) ATOMIC SPECTRA|2 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (H.W) INTRODUCTION|4 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (C.W) ALPHARAY SCATTERING|2 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

  • CAPACITANCE

    NARAYNA|Exercise Previous IIT-JEE|16 Videos

Similar Questions

Explore conceptually related problems

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

The de Broglie wavelength of an electron in the n^(th) Bohr orbit is related to the radius R of the orbit as

The de-broglie wavelength of the electron in the second Bohr orbit is (given the radius of the first orbit r_1 = 0.53 Å)

In hydrogen atom,the de Broglie wavelength of an electron in the second Bohr's orbit is ? Given that Bohr radius a_(0)=52.9 pm

Calculate the velocity of an electron in the first Borh's orbit of hydrogen atom (given r = a_(0)) b. Find de Broglie wavelength of the electron in the first Bohr's orbit c. Find the orbital angular momentum of 2p orbital in terms of h//2pi units

If the radius of the first Bohr orbit is r, then the de broglie wavelength of the electron in the 4th orbit will be

If the radius of the Bohr's orbit is r then the de Broglie wavelength of the electron in the third orbit will be

de-Broglie wavelength of an electron in the nth Bohr orbit is lambda_(n) and the angular momentum is J_(n) then