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The radius of first Bohr orbit is x, the...

The radius of first Bohr orbit is x, then de-Broglie wavelength of electron in 3rd orbit is nearly

A

`2pi x`

B

`6pi x`

C

`9 x`

D

`x//3`

Text Solution

Verified by Experts

The correct Answer is:
B

`mvr = (nh)/(2pi (r = (r_0 n^2)/(Z)) r_(0)=x `
`2pi r = n lambda rArr lambda =( 2pi r)/( n) =6 pi x`.
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