Home
Class 12
PHYSICS
The de-broglie wavelength of the electro...

The de-broglie wavelength of the electron in the second Bohr orbit is (given the radius of the first orbit `r_1` = 0.53 Å)

A

`3.33A^@`

B

`6.66A^@`

C

`9.90A^@`

D

`1.06A^@`

Text Solution

Verified by Experts

The correct Answer is:
B
` 2pi r = n lambda , therefore = (2pi r)/(n) = (2pi r_(0)n^2)/(n) = 2pi r_(0) n`
Promotional Banner

Topper's Solved these Questions

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (C.W) ATOMIC SPECTRA|2 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (H.W) INTRODUCTION|4 Videos

  • ATOMS

    NARAYNA|Exercise EXERCISE -2 (C.W) ALPHARAY SCATTERING|2 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

  • CAPACITANCE

    NARAYNA|Exercise Previous IIT-JEE|16 Videos

Similar Questions

Explore conceptually related problems

The de-Broglie wavelength of an electron in the first Bohr orbit is

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

The de broglie wavelength of an electron in the first Bohr orbit is equal to

The de Broglie wavelength of an electron in the n^(th) Bohr orbit is related to the radius R of the orbit as

The De Broglie wavelenght associated with electron in n Bohr orbit is

The de-Broglie wavelength of the electron in the ground state of the hyddrogen atom is (Given, radius of the first orbit of hydrogen atom=0.53Å)

In hydrogen atom,the de Broglie wavelength of an electron in the second Bohr's orbit is ? Given that Bohr radius a_(0)=52.9 pm