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.(13)Al^(27)+alpha-particle rarrneutron ...

`._(13)Al^(27)+alpha-`particle `rarr`neutron `+'X'` then `'X'` is

A

`"" _(15) P^(31)`

B

`"" _(14) Si ^(30)`

C

`"" _(15) P^(30)`

D

`""_(15) Si ^(30)`

Text Solution

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The correct Answer is:
C
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