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The atomic mass of .(7)N^(15) is 15.0001...

The atomic mass of `._(7)N^(15)` is `15.000108 "amu"` and that of `._(8)O^(16)` is `15.994915 "amu"`. The minimum energy required to remove the least tightly bound proton is ( mass of proton is `1.007825 "amu"`)

A

`0.01 3018 ` amu

B

`12.13 ` MeV

C

`13.018` meV

D

`12.13 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta m = m _(p)+ m _("nitrogen")-m _("oxygen")` energy required `= Deltam xx 931.5 MeV`
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