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If the activity of .^(108)Ag is 3 micro ...

If the activity of `.^(108)Ag` is 3 micro curie, the number of atoms present in it are `(lambda=0.005 sec^(-1))`

A

`2.2 x 10 ^(7)`

B

`2.2 x 10 ^(6)`

C

`2.2 x 10^(5)`

D

`2.2 x 10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda = (((dN)/(dt )))/(N)`
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