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If M(A,Z), M(p)and M(n) denote the masse...

If `M(A,Z)`, `M_(p)and M_(n)` denote the masses of the nucleus `._(Z)X^(A)`, proton and neutron respectively in units of U (where`1U=931MeV//c^(2)`) and B.E. represents its B.E. in MeV, then

A

`M (A,Z) = ZM_(p) + (A -Z) M _(n) - BE`

B

`M (A, Z) = ZM_(p) + (A-Z) M _(n) - BE //C ^(2)`

C

`M (A,Z) = ZM_(p) + (A-Z) M _(n) + Be //C ^(2)`

D

`M (A,Z) = ZM_(p) + (A-Z) M _(n)+ BE`

Text Solution

Verified by Experts

The correct Answer is:
C

`ZM_(p)+ (A-Z) M _(n) - M (A,Z)` = mass defect `=(BE)/(c ^(2))`
`implies M (A,Z) = ZM_(p) + (A-Z) M _(n) - (BE)/(c ^(2))`
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