If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :

Options

A. `4.8`
B. `3.6`
C. `2.4`
D. `1.2`

Answer

A

Explanation

Nuclear radius, `R = R _(0) A ^(1//3)`
Where `R _(0)` is a constant and A is the mass number `therefore (R _(Al))/(R _(Cu))= ((27 )^(1//3))/((64)^(1//3))= 3/4`
`or R _(Cu)=4/3xx R _(Al) =4/3 3.6 ` fermi` =4.8` rermi