If radius of the `._(13)^(27)Al` nucleus is taken to be `R_(AI)`, then the radius of `._(53)^(125)Te` nucleus is nearly

Options

A. `3/5 R _(Al)`
B. `((13)/(53)) ^(1//3) R _(Al) `
C. `((53)/(13)) ^(1//3)R _(Al)`
D. `5/3 R _(Al)`

Answer

D

Explanation

Radius of the nucleus `R = R _(0)A^(1//3)`
`therefore (R_(A))/(R _(T e))= ((A _(A l))/(A _(Te)))^(1//3)`
Here ` A _(Al) = 27, A _(Te) = 125, R _(Te) =` ?
`(R _(Al ))/( R _(T e))= ((27)/(125))^(1//3) = 3/5 implies R _(Te) = 5/3 R _(Al)`