When an `alpha-`particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on `m` as :

Options

A. `(1)/(m^(2)) `
B. `m `
C. `1/m`
D. `(1)/(sqrtm)`

Answer

C

Explanation

Distance of closest approach when anparticle of mass m moving with velocity v is bombarded on a heavy nucleus of charge Ze, is given by
`r _(0) = (Ze ^(2))/(pi in _(0) mv ^(2) ) therefore r _(0) alpha (1)/(m)`