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The reverse bias in a junction diode is ...

The reverse bias in a junction diode is changed from `5V` to `15 V` then the value of current changes from `38 mu A` to `88 mu A`. The resistance of junction diode will be.

A

`4x10^(5) Omega`

B

`3x10^(5) Omega`

C

`2x10^(5) Omega`

D

`10^(6) Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`R=(DeltaV)/(Deltal)=(15-5)/((88-38)xx10^(-6))=(10)/(50xx10^(-6))`
`=(10^(6))/(5)=(10)xx10^(5)=2xx10^(5) Omega`
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