A potential barrier of `0.5V` exists across a p-n junction . If the widht of depletion layer is `10^(-6)`m, then intensity of electric field in this region will be

Options

A. `1xx10^(6)V//m`
B. `5x 10^(5)V//m`
C. `4x10^(4)V//m`
D. `2x10^(6)V//m`

Explanation

To find the intensity of the electric field (E) across a p-n junction with a given potential barrier (V) and width of the depletion layer (D), we can use the formula:

\[ E = \frac{V}{D} \]

### Step-by-step Solution:

1. **Identify the given values:**
- Potential barrier, \( V = 0.5 \, \text{V} \)
- Width of the depletion layer, \( D = 10^{-6} \, \text{m} \)

2. **Substitute the values into the formula:**
\[ E = \frac{0.5 \, \text{V}}{10^{-6} \, \text{m}} \]

3. **Calculate the electric field:**
- First, calculate \( \frac{0.5}{10^{-6}} \):
\[ E = 0.5 \times 10^{6} \, \text{V/m} \]
- This simplifies to:
\[ E = 5 \times 10^{5} \, \text{V/m} \]

4. **Final result:**
The intensity of the electric field in the depletion layer is:
\[ E = 5 \times 10^{5} \, \text{V/m} \]

### Conclusion:
The correct answer is \( 5 \times 10^{5} \, \text{V/m} \).