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A cell of emf. 4.5 V is connected to a j...

A cell of emf. `4.5 V` is connected to a junction diode whose barrier potential is `0.7 V`. If the external resistance in the circuit is `190 Omega`. The current in the circuit is

A

20 mA

B

2mA

C

23 mA

D

200 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`V=4.5-0.7=3.8V, R=190 Omega, i=(V)/(R)`
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