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In the circuit shown in figure (1), the ...

In the circuit shown in figure (1), the `V_(0),I_(1),I_(D_(1))`, and `I_(D_(3))` are respectively.
(A)

A

`0.5V,25mA,15mA`

B

`0.7V,28.18mA,14.09mA`

C

`0.4V,15mA,20mA`

D

`0.3V,15.06mA,20.18mA`

Text Solution

Verified by Experts

The correct Answer is:
B
Since applied voltage is greater then 0.7 V and direction of current is same as direction of arrow head, both the diodes are in ..on.. state (see above figure(2)). Now `V_(0)` is parallel to `D_(1)andD_(2)`. Hence `V_(0)=0.7V`
Current `I_(1)=(V_(R))/(R)=(E-V_(D))/(R)=(10V-0.7V)/(0.33kOmega)`
=28.18 mA
Both the silicon diodes have similar characteristics.
Hence `I_(D_(1))=I_(D_(2))=(I_(1))/(2)=14.09mA`
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