If two particles each of mass `m` are placed at the two vertices of an equilateral triangle of side `a`, then the resultant gravitational force on mass `m` placed at the third vertex is

Explanation

`F_(R)=sqrt(F_(A)^(2)+F_(B)^(2)+2F_(A)F_(B)cos 60^(@))`
`=sqrt(3)F[ :. F_(A)=F_(B)=F]`
`F_(R)=sqrt(3)[(Gm^(2))/(a^(2))]`