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A particle is fired vertically upward fom earth's surface and it goes up to a maximum height of 6400 km. find the initial speed of particle.

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TE. On the surface of the earth =TE. At the highest point.
`1/2mV^(2)-(GMm)/R=0-(GMm)/(R+H)`
`implies1/2mV^(2)=(mgh)/([1+h/R])`
Given `h=R=6400Km`
So `V^(2)=ghimpliesV=sqrt(gh)`
`impliesV=sqrt(10xx6400xx10^(3))=8Km//s`
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