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In a satellite if the time of revolution...

In a satellite if the time of revolution is `T`, then kinetic energy is proportional to

A

`1/T`

B

`1/(T^(2))`

C

`1/(T^(3))`

D

`T^(-2//3)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • In an orbit if the time of revolution of satellite is T , then PE is proportional to

    A
    `T^(1//3)`
    B
    `T^(3)`
    C
    `T^(-2//3)`
    D
    `T^(-4//3)`

  • Let kinetic energy of a satellite is x, then its time of revolution T is proportional to

    A
    `x^(-3)`
    B
    `x^(-3//2)`
    C
    `x^(-1)`
    D
    `sqrt(x)`

  • Radius of orbit of satellite of earth is R . Its kinetic energy is proportional to

    A
    `1/R`
    B
    `1/(sqrt(R))`
    C
    `R`
    D
    `1/(R^(3//2))`

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