The period of revolution of an earth's s...

The period of revolution of an earth's satellite close to the surface of the earth is `60` minute. The period of another the earth's satellite in an orbit at a distance of three times earth's radius from its surface will be (in minutes)

`90xxsqrt(8)`

`270`

`480`

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The correct Answer is:

From Kepler.s 3rd law `T^(2)prop r^(3)`

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