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A particle hanging from a massless sprin...

A particle hanging from a massless spring stretches it by `2 cm` at the earth's surface. How much will the same particle stretch the spring at a height Of `2624Km` from the surface of the earth? (Radius of the earth`=6400 km`)

A

1cm

B

2cm

C

3cm

D

4cm

Text Solution

Verified by Experts

The correct Answer is:
A
`mg=Kx,x prop g` Here `(g_(h))/g=(R^(2))/((R+h)^(2))`
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