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If g is acceleration due to gravity on t...

If `g` is acceleration due to gravity on the surface of the earth, having radius `R`, the height at which the acceleration due to gravity reduces to `g//2` is

A

`R//2`

B

`sqrt(2)R`

C

`R/(sqrt(2))`

D

`(sqrt(2)-1)R`

Text Solution

Verified by Experts

The correct Answer is:
D
`(g_(h))/g=(R^(2))/((R+h)^(2))` Given `g_(h)=g/2`
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