If the escape velocity on the earth is 1...

If the escape velocity on the earth is `11.2km-s^-1`, its value for a planet having double the radius and 8 times the mass of earth is

11.2

22.4

5.6

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The correct Answer is:

`v_(e)=sqrt((2GM)/R)implies(v_(1))/(v_(2))=sqrt((M_(1))/(M_(2))(R_(2))/(R_(1)))`

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