Acceleration due to gravity on moon is 1...

Acceleration due to gravity on moon is `1//6` of the acceleration due to gravity on earth. If the ratio of densities of earth `(rho_(e))` and moon `(rho_(m))` is `((rho_(e))/(rho_(m)))=5/3` then radius of moon `(R_(m))` in terms of `R_(e)` will be

`5/18 R_(e)`

`1/6R_(e)`

`3/18R_(e)`

`1/(2sqrt(3))R_(e)`

Text Solution

Verified by Experts

The correct Answer is:

`g=4/3pi Grrhoimpliesg prop R rho`

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