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If the value of `g` at the surface of the earth is `9.8 m//sec^(2)`, then the value of `g` at a place `480` km above the surface of the earth will be (Radius of the earth is `6400` km)

A

`8.4m//s^(2)`

B

`9.8m//s^(2)`

C

`7.2m//s^(2)`

D

`4.2m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`g.=(gR^(2))/((R+h)^(2))=8.4ms^(-2)`
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