A spherical planet far out in space has a mass `M_(0)` and diameter `D_(0)`. A particle of mass m falling freely near the surface of this planet will experience an accelertion due to gravity which is equal to

Options

A. `4GM_(P)m//D_(P)^(2)`
B. `4GM_(P)//D_(P)^(2)`
C. `GM_(P)m//D_(P)^(2)`
D. `GM_(P)//D_(P)^(2)`

Answer

B

Explanation

`g=(GM_(p))/(R_(P)^(2))=(4GM_(P))/(D_(P)^(2))`