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A geostationary satellite is orbiting th...

A geostationary satellite is orbiting the earth at a height of `5R` above the surface of the earth, `2R` being the radius of the earth. The time period of another satellite in hours at a height of `2R` form the surface of the earth is

A

`6/(sqrt(2))`

B

5

C

10

D

`6sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`T^(2) prop r^(3)`
`(24/T)=((6R)/(3R))^(3//2)`
`T=6sqrt(2)`
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NARAYNA-GRAVITATION-EXERCISE -III
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  2. A spherical planet far out in space has a mass M(0) and diameter D(0)....

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  4. If v(e) is escape velocity and v(0), is orbital velocity of satellite ...

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  5. Which one of the following plots represents the variation of the gravi...

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  6. An artificial satellite moving in circular orbit around the earth has ...

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  7. A lauching vehicle carrying an artificial satellite of mass m is set f...

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  8. A body of mass m taken form the earth's surface to the height is equal...

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  9. Infinite number of bodies, each of mass 2kg, are situated on x-axis at...

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  10. The value of ‘ g ’ at a particular point is 9.8 m//s^(2) . Suppose the...

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  11. The escape velocity for the earth is 11.2 km / sec . The mass of anoth...

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  15. The orbital velocity of an artifical satellite in a circular orbit jus...

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  16. Change in acceleration due to gravity is same upto a height h from the...

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  17. Kepler's third law states that square of period revolution (T) of a pl...

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  18. Two spherical bodies of mass M and 5M & radii R & 2R respectively are ...

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  19. A satellite S is moving in an elliptical orbit around the earth. The m...

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