Home
Class 11
PHYSICS
The value of ‘ g ’ at a particular point...

The value of ‘ g ’ at a particular point is `9.8 m//s^(2)` . Suppose the earth suddenly shrinks uniformly to half its present size without losing any mass. The value of ‘ g ’ at the same point (assuming that the distance of the point from the centre of earth does not shrink) will now be

A

`9.8ms^(-2)`

B

`4.9ms^(-2)`

C

`19.6ms^(-2)`

D

`39.2ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`g=(GM)/(R^(2))` both M and R are constants
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    NARAYNA|Exercise EXERCISE -IV|40 Videos
  • GRAVITATION

    NARAYNA|Exercise EXERCISE -II (H.W.)|34 Videos
  • FRICTION

    NARAYNA|Exercise Passage type of questions I|6 Videos
  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos

Similar Questions

Explore conceptually related problems

The value of g at a particular point is 10 m s^(-2) . Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of g at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be

If the earth suddenly shrinks (without changing mass) to half of its present radius, the acceleration due to gravity will be

If the earth suddenly contracted to half of its present radius without losing any mass, how many hours would there be in a day? (hint: Apply the principle of conservation of angular momentum).

If the earth suddenly shrinks (without changing mass) to half of its present radius, then acceleration due to gravity will be

Assertion : If radius of earth suddenly shrinks to half its present without changing its mass value, then the period of an earth's satellite will not change Reason : Time period of a satellite does not upon the mass of earth.

If g denotes the value of acceleration due to gravity at a point distance r from the centre of earth of radius R . If r lt R , then

NARAYNA-GRAVITATION-EXERCISE -III
  1. An artificial satellite moving in circular orbit around the earth has ...

    Text Solution

    |

  2. A lauching vehicle carrying an artificial satellite of mass m is set f...

    Text Solution

    |

  3. A body of mass m taken form the earth's surface to the height is equal...

    Text Solution

    |

  4. Infinite number of bodies, each of mass 2kg, are situated on x-axis at...

    Text Solution

    |

  5. The value of ‘ g ’ at a particular point is 9.8 m//s^(2) . Suppose the...

    Text Solution

    |

  6. The escape velocity for the earth is 11.2 km / sec . The mass of anoth...

    Text Solution

    |

  7. a projectile is fired from the surface of the earth with a velocity of...

    Text Solution

    |

  8. A black hole is an object whose gravitational field is so strong that ...

    Text Solution

    |

  9. Dependence of intensity of gravitational field (E) of earth with dista...

    Text Solution

    |

  10. The orbital velocity of an artifical satellite in a circular orbit jus...

    Text Solution

    |

  11. Change in acceleration due to gravity is same upto a height h from the...

    Text Solution

    |

  12. Kepler's third law states that square of period revolution (T) of a pl...

    Text Solution

    |

  13. Two spherical bodies of mass M and 5M & radii R & 2R respectively are ...

    Text Solution

    |

  14. A satellite S is moving in an elliptical orbit around the earth. The m...

    Text Solution

    |

  15. A remote-sensing satellite of earth revolves in a circular orbit at a ...

    Text Solution

    |

  16. Given raduis of earth 'R' and length of a day 'T' the height of a geos...

    Text Solution

    |

  17. A uniform ring of mas m and radius a is placed directly above a unifor...

    Text Solution

    |

  18. The ratio of escape velocity at earth (v(e)) to the escape velocity at...

    Text Solution

    |

  19. The escape velocity from the earth is about 11 km/s. The escape veloci...

    Text Solution

    |

  20. A body of mass 2 m is placed one earth's surface. Calculate the change...

    Text Solution

    |