a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

Options

A. 3.5
B. 5.9
C. 16.3
D. 110.8

Answer

A

Explanation

`y=x tan theta- g/(2u^(2)cos^(2) theta) x^(2)`
`g/(u^(2))=` constant
`9.8/25=(g.)/9impliesg.=3.5ms^(-2)`