A stone is swinging in a horizontal circle of diameter `0.8m` at `30 rev//min`. A distant light causes a shadow of the stone on a nearly wall. The amplitude and period of the SHM for the shadow of the stone are

Explanation

The amplitude is the radius of the circle
`rArr R = 0.8//2," "A = 0.4 m`
The frequency and period of the shadow are same as that of the circular motion. So
`omega = 30 rev//min = (30xx2pi)/(60) rad//s`
`omega = pi rad//s, 2pif = pi rArr f = (1)/(2)Hz`
Time period T `= (1)/(f)` T = 2s