Home
Class 11
PHYSICS
Two simple harmonic motions are represen...

Two simple harmonic motions are represented by the equations `y_(1) = 10 sin (3pit + (pi)/(4))`
and `y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t)`. Their amplitudes are in the ratio of

Text Solution

Verified by Experts

`y_(2) = 5 (sin 4 pi t + sqrt(3) cos 4 pi t)`
`=5 xx 2 ((1)/(2) sin 4 pi t + (sqrt(3))/(2) cos 4 pi t)`
`= 10 ["cos"(pi)/(3) sin 4 pi t + "sin" (pi)/(3) cos 4 pi t]`
`rArr" "y_(2) = 10 sin (4pi t + (pi)/(3))`
Hence ratio of two amplitudes is `(A_(1))/(A_(2)) = (10)/(10) = 1 : 1`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise EVALUATE YOURSELF - 1|7 Videos
  • OSCILLATIONS

    NARAYNA|Exercise EVALUATE YOURSELF - 2|4 Videos
  • OSCILLATIONS

    NARAYNA|Exercise DAMPED OSCILLATIONS|1 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos
  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

Two simple harmonic motions are represented by the equations y_(1) = 10 sin(3pit + pi//4) and y_(2) = 5(sin 3pit + sqrt(3)cos 3pit) their amplitude are in the ratio of ………… .

Two simple harmonic motion, are represented by the equations y _(1) = 10 sin ( 3 pi t + (pi)/(3)) y _(2) = 5 ( sin 3 pi t + sqrt3 cos 3 pi t ) Ratio of amplitude of y _(1) to y _(2) = x :1. The value of x is __________

The simple harmonic motions are represented by the equations: y_(1)=10sin((pi)/(4))(12t+1), y_(2)=5(sin3pit+sqrt(3)))

Two simple harmonic motions are represented by the equations y_(1)=2(sqrt(3)cos3 pi t+sin3 pi t) and y_(2)=3sin(6 pi t+pi/6)

Statement-I : Two simple harmonic motions are given by y_(1) = 10sin (3pi t+(pi)/(4)) and y_(2) = 5(sin 3pit +sqrt(3) cos 3pi t) . These have amplitudes in the ratio 1:1 . Statement-II : y_(1) & y_(2) respresents two waves of amplitudes 5 & 5sqrt(3) . So the resultant amplitude is 10 .

Two simple harmonic motions are represented by the equations : x_1 = 5 sin (2 pi t + pi//4 ) , x_2 = 5^(2) (sin2 pi t + cos2 pi t) What is the ratio of their amplitudes ?

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

If two SHMs are represented by equations y_(1) = 5 sin (2pi t + pi//6) and y_(2) = 5 [sin (3pi) + sqrt3 cos (3pi t)] . Find the ratio of their amplitudes.

Two simple harmonic motion are represent by the following equations y_(1) = 10 sin (pi//4) (12 t + 1) y_(2) = 5 (sin 3 theta t + sqrt3 cos 3 theta t) Here t is in seconds. Find out the ratio of their amplitudes.What are the time period of the two motion?

Two simple harmonic motions are represented by the equations y_(1) = 8 sin(pi)/(4)(10t + 2),y_(2) = 6(sin 5pit + sqrt(3) cos 5omegat) IF the ratio of amplitudes of y_(1) and y_(2) is alpha and their respective ratio of time periods is beta , then find beta//alpha .

NARAYNA-OSCILLATIONS-ILLUSTRATION
  1. Two bodies A and B of equal mass are suspended from two separate massl...

    Text Solution

    |

  2. The time period and the amplitude of a simple pendulum are 4 seconds a...

    Text Solution

    |

  3. Two simple harmonic motions are represented by the equations y(1) = 10...

    Text Solution

    |

  4. A simple pendulam with a solid metal bob has a period T. The metal bob...

    Text Solution

    |

  5. The system of simple pendulum is immersed in liquid of a density rho(l...

    Text Solution

    |

  6. Find the time period in each of the following cases, if the mass is pu...

    Text Solution

    |

  7. The system is pulled to an elongation A and Then released. Find the mi...

    Text Solution

    |

  8. A 50 gm mass at the end of a spring vibrates in SHM. The amplitude of ...

    Text Solution

    |

  9. The left block in figure collides inelastically with the right block a...

    Text Solution

    |

  10. One end of a spring of force constant k is fixed to a vertical wall an...

    Text Solution

    |

  11. A horizontal platform vibrate up and down with a simple harmonic motio...

    Text Solution

    |

  12. Find time period of oscillation of the system.

    Text Solution

    |

  13. The surface shown in the diagram are smooth and all collisions are ela...

    Text Solution

    |

  14. Total mechanical energy of an oscillator is 160 J. Its force constant ...

    Text Solution

    |

  15. A point particle of mass 0.1kg is executing SHM of amplitude 0.1m. Whe...

    Text Solution

    |

  16. The average energy in one time period in simple harmonic motion is

    Text Solution

    |

  17. A particle moves on the X-axis according to the equation x = x(0) sin^...

    Text Solution

    |

  18. A particle of mass m is dropped in a tunnel dug along the diameter of ...

    Text Solution

    |

  19. A disc of mass 'm' is suspended at a point R/2 above its centre. Find ...

    Text Solution

    |

  20. A simple pendulum oscillates simple harmonically. The tension in the s...

    Text Solution

    |