A simple pendulam with a solid metal bob has a period T. The metal bob is now immersed in a liquid having density one-teeth that of the metal of the bob. The liquid is non-viscuous. Now the period of the same pendulum with its bob remaining all the time in the liquid will be

Explanation

Let apparent acceleration due to gravity because of force of buoyancy be g.. Then
`g. = g(1 - (rho_(l))/(rho_(s)))" "rho_(l) = (rho_(s))/(10)" "g. = g(1 - (1)/(10)) = (9)/(10)g`
`T alpha (1)/(sqrt(g)) rArr T. = sqrt((10)/(9)) " "T rArr (2pi)/(omega.) = sqrt((10)/(9)) (2pi)/(omega)`
`rArr omega. = sqrt((9)/(10)) omega`