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The end of the rod which is connected to the spring is pushed down and released. Find time period of oscillation of the rod ?

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`tau_(res) =-(Ky)l =- (K l theta)l =- Kl^(2)theta`
or `-I omega^(2)theta =- Kl^(2)theta`
or, `-((1)/(3)ml^(2)) theta (omega)^(2) =-Kl^(2)theta`
`rArr" "omega = sqrt((3K)/(m))`
`therefore" "T = 2pi sqrt((m)/(3K))`
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