The frequency of a particle performing `SHM` is `12Hz`. Its amplitude is `4cm`. Its initial displacement is `2cm` towards positive exterme positions. Its equation for displacement is

Options

A. `x = 0.04 cos (24 pi t + (pi)/(6)) m`
B. `x = 0.04 sin (24 pi t) m`
C. `x = 0.04 sin (24 pi t + (pi)/(6))m`
D. `x = 0.04 cos (24 pi t)m`

Answer

C

Explanation

`f = 12 rArr omega = 2pi f = 24 pi`
`A = 4cm rArr 0.04 m`
Initial displacement `y = A sin phi`
`2 = 4 sin phi = phi = (pi)/(6)`
So displacement equation is `x = 0.04 sin (24 pi + (pi)/(6))`