Home
Class 11
PHYSICS
A particle is executing simple harmonic ...

A particle is executing simple harmonic motion between exterme positions given by `(-1,-2,-3)cm` and `(1,2,1)cm`. Its amplitude of oscillation is

A

6 cm

B

4 cm

C

2 cm

D

3 cm

Text Solution

Verified by Experts

The correct Answer is:
D
Distance between two extremes is = 2A
`2A = sqrt((1-(-1)^(2) + 2 - (-2)^(2) + 1-(-3)^(2)))`
`= sqrt(4 + 16 + 16) = sqrt(36) = 6 cm rArr A = 3 cm`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - I (H.W)|66 Videos

  • OSCILLATIONS

    NARAYNA|Exercise EXERCISE - II (C.W)|27 Videos

  • OSCILLATIONS

    NARAYNA|Exercise C. U . Q|75 Videos

  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

  • PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|10 Videos

Similar Questions

Explore conceptually related problems

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm and 8 cm s^(-1) respectively . If the angular frequency of the particle is 2 "rad s" ^(-1) , then the amplitude of oscillation (in cm) is

A particle is executing simple harmonic motion with a time period of 2s and amplitude 10 cm. Calculate its velocity and acceleration 2 seconds after starting from mean position.

A particle is executing simple harmonic motion. The velocity of the particle is 10 m s^(-1) . What at a distance of 5 cm from mean position and 8 cm s^(-1) when at a distance of 12 cm from mean position. What will be the amplitude of motion ?

A particle is executing simple harmonic motion with time period of 4 s and amplitude 10 cm. Calculate displacement, velocity after (1)/(2) second starting from mean position.

The resultant force acting on a particle executing simple harmonic motion is 4N when it is 5cm away from the centre of oscillation. Find the spring constant.

A particle is executing simple harmonic motion with an amplitude of 10 cm and time period of 4s. Calculate its displacement, velocity and acceleration after 1/2 seconds, starting from the mean position.

NARAYNA-OSCILLATIONS-EXERCISE - I (C.W)
  1. A particle moves according to the law x=r cos.(pit)/(2). The distance ...

    Text Solution

    |

  2. Amplitude of oscillation of a particle that executes SHM is 2cm. Its d...

    Text Solution

    |

  3. A particle is executing simple harmonic motion between exterme positio...

    Text Solution

    |

  4. The period of oscillation of a particle in SHM is 4s and its amplitude...

    Text Solution

    |

  5. The displacement of a particle in SHM is x = 3sin (20 pit) +4 cos(20pi...

    Text Solution

    |

  6. Displacement time equation of a particle executing SHM is, x = 10 sin ...

    Text Solution

    |

  7. The time period of a simple harmonic motion is 8 s At t=0. it is at th...

    Text Solution

    |

  8. A simple harmonic motion is represented by F(t)=10sin(20t+0.5). The am...

    Text Solution

    |

  9. A simple harmonic oscillation has an amplitude A and time period T. Th...

    Text Solution

    |

  10. The motion of a particle is given x = A sin omega t + B cos omega t Th...

    Text Solution

    |

  11. The displacement of a particle along the x-axis is given by x = a sin^...

    Text Solution

    |

  12. Out of the following functions representing motion of a particle which...

    Text Solution

    |

  13. The equation of S.H.M. isy=a sin (2 pint + a), then its phase at time...

    Text Solution

    |

  14. A particle starts from rest at the extreme position and makes SHM with...

    Text Solution

    |

  15. A particle executing simple harmonic motion along y -axis has its moti...

    Text Solution

    |

  16. The equation describing the motion of a simple harmonic oscillator alo...

    Text Solution

    |

  17. A particle in SHM has a period of 4s .It takes time t(1) to start from...

    Text Solution

    |

  18. The equation of the displacement of two particles making SHM are repre...

    Text Solution

    |

  19. Which of the following equation does not represent a simple harmonic m...

    Text Solution

    |

  20. The time period of oscillation of a particle that executes SHM is 1.2s...

    Text Solution

    |