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Displacement time equation of a particle...

Displacement time equation of a particle executing `SHM` is, `x = 10 sin ((pi)/(3)t+(pi)/(6))cm`. The distance covered by particle in `3s` is

A

5 cm

B

20 cm

C

10 cm

D

15 cm

Text Solution

Verified by Experts

The correct Answer is:
B
At t = 0 `x_(0) = "10 sin" (pi)/(6) = 5 cm`
Time period `= (2pi)/(omega) = (2pi)/(pi) xx 3 = 6s`
In 3s it covers a distance of 20 cm
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NARAYNA-OSCILLATIONS-EXERCISE - I (C.W)
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