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A simple harmonic oscillator is of mass ...

A simple harmonic oscillator is of mass `0.100 kg`. It is oscillating with a frequency of `(5)/(pi) Hz`. If its amplitude of vibrations is `5cm`, then force acting on the particle at its exterme position is

A

2 N

B

1.5 N

C

1 N

D

0.5 N

Text Solution

Verified by Experts

The correct Answer is:
D
`F_("extreme") = ma_(max) = m omega^(2)A = 0.1 xx (10)^(2) xx 5 xx 10^(-2) = 0.5 N`
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NARAYNA-OSCILLATIONS-EXERCISE - I (C.W)
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  4. A body executing SHM has a maximum velocity of 1ms^(-1) and a maximum ...

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  5. The velocity of a particle in SHM at the instant when it is 0.6cm away...

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  6. The equation of motion of a particle started at t=0 is given by x=5sin...

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  7. A particle executes simple harmonic motion with a period of 16s. At ti...

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  8. A particle is moving in a circel of radius R = 1m with constant speed ...

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  9. A particle performing SHM having amplitude 'a' possesses velocity ((3)...

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  14. The length of a pendulum changes from 1m to 1.21m. The percentage chan...

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  16. The bob of a simple pendulum of mass 100g is oscillating with a time p...

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  17. Three simple pendulums have length of strings 49cms, 48 cms and 47 cms...

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  18. The period of a simple pendulum is found to increases by 50% when the ...

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  19. In a spring block system if length of the spring is increased by 4%, t...

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  20. A spring of natural length 80cm with a load has a length of 100cm. If ...

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