A body executing `SHM` has a maximum velocity of `1ms^(-1)` and a maximum acceleration of `4ms^(-1)`. Its time period of oscillation is

Options

A. 1
B. 0.75
C. 0.5
D. 0.25

Answer

D

Explanation

`V_(max) = A omega = 1" "a_(max) = A omega^(2) = 4`
`rArr (a_(max))/(V_(max)) = omega = 4, " "V_(max) = A xx 4 = 1 rArr A = (1)/(4)`