A particle is moving in a circel of radius `R = 1m` with constant speed `v =4 m//s`. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circel is

Options

A. `(1)/(16) s^(2)`
B. `(1)/(2) s^(2)`
C. `2 s^(2)`
D. `16 s^(2)`

Answer

A

Explanation

`V = R omega" "4 = 1 xx omega" "rArr omega = 4`
`a = omega^(2)y" "rArr (y)/(a) = (1)/(omega^(2))" "(y)/(a) = (1)/(16)s^(2)`