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A spring of force constant k is cut into...

A spring of force constant `k` is cut into two parts whose lengths are in the ratio `1:2`. The two parts are now connected in parallel and a block of mass `m` is suspended at the end of the combined spring. The period of oscillation of block is

A

`2pi sqrt((2m)/(9K))`

B

`2pi sqrt((m)/(9K))`

C

`2pi sqrt((2m)/(5K))`

D

`2pi sqrt((m)/(5K))`

Text Solution

Verified by Experts

The correct Answer is:
A

`l_(1) = (l)/(2), l_(2) = (2l)/(3)`
`(K)/(K_(1)) = ((l)/(3))/(l) rArr K_(1) = 3K`
`(K)/(K_(2)) = ((2l)/(3))/(l) rArr K_(2) = (3)/(2)K`
In parallel combination
`K_(p) = K_(1) + K_(2) = 3K + (3K)/(2) = (9K)/(2)`
`T = 2pi sqrt((2m)/(9K))`
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NARAYNA-OSCILLATIONS-EXERCISE - I (C.W)
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