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The amplitude of oscillation of particle...

The amplitude of oscillation of particles in `SHM` is `sqrt(3)cm`. The displacement from mean position at which its potential and kinetic energies are in the ratio `1:2` is

A

1 cm

B

0.866 cm

C

`(1)/(sqrt(3))` cm

D

`sqrt(2)` cm

Text Solution

Verified by Experts

The correct Answer is:
A
`A = sqrt(3)cm rArr (y^(2))/(3-y^(2))=(1)/(2) rArr 2y^(2) =3 - y^(2)rArr 3y^(2) = 3 rArr y = 1 cm`
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