Find the average kinetic energy of a simple harmonic oscillator if its total energy is `10` joule and minimum potential energy is `2` joule.

Options

A. 1J
B. 4J
C. 8J
D. 5J

Answer

B

Explanation

`KE_(avg) = (KE_(max) + KE_(min))/(2)`
`TE = KE_(max) + PE_(min)`
`10 = KE_(max) + 2 rArr KE_(max) = 8`
`KE_(avg) = (KE_(max) + KE_(min))/(2) = 4J`