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Two particles undergo SHM along the same...

Two particles undergo SHM along the same line with the same time period (T) and equal amplitude (A). At a particular instant one is at x = -A and the other is at x = 0. If they start moving in the same direction then they will cross each other at

(i) `t = (4T)/(3)`
(ii) `t = (3T)/(8)`
(iii) `x = (A)/(2)`
(iv) `x = (A)/(sqrt(2))`

A

only i, iii are correct

B

only i, iv are correct

C

only ii, iii are correct

D

only ii, iv are correct

Text Solution

Verified by Experts

The correct Answer is:
D

Time after which they meet `t = (T)/(4) + (T)/(8), t = (T)/(8), x = A cos (omega t)`
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NARAYNA-OSCILLATIONS-EXERCISE - II (C.W)
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  7. The x-t graph of a particle undergoing simple harmonic motion is shown...

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  8. The displacement - time graph of a particle executing SHM is as shown ...

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  11. Match the following {:("List - I","List - II"),("(a) acceleration","...

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  12. For a particle executing SHM along a straight line (displacement is me...

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