The length of a second's pendulum on the surface of the moon, where g is `1//6^(th)` if the value of g on the surface of the

Options

A. 1/5 m
B. 1/6 m
C. 1/3 m
D. 1m

Answer

B

Explanation

`T = 2pi sqrt((l)/(g))" "(l_(1))/(g_(1)) = (l_(2))/(g_(2))`
`(1)/(g) = (l^(2))/((g)/(6))" "l_(2) = (1)/(6)`