Solve the equation :`27 x^2-10 x+1=0`

Explanation

We know the roots of the quadratic equation `Ax^2+Bx+C=0 `are

`x=(−B±sqrt(B^2−4AC))/(2A)`

​​The given equation is
`27x^2-10x+1=0`

for the given equation, `B^2−4AC=(-10)^2−4(27)(1)=−8`

So the roots are

`x=(-(-10)±sqrt(−8))/(2*27)`

`x=((10)±sqrt(−8))/(54)`

​​`x=(10±sqrt(8)​i)/(54)`

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