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Mg(OH)(2) in the form of Milk of Magnesi...

`Mg(OH)_(2)` in the form of Milk of Magnesia is used to neutralize excess stomach acid. How many moles of stomach acid can be neutralized by 1.00g of `Mg(OH)_(2)`?
`{:("Molar Mass" , g//mol), ((mg(OH)_(2)), 58.33):}`

A

0.0171

B

0.0343

C

0.686

D

1.25

Text Solution

Verified by Experts

The correct Answer is:
B
`Mg(OH)_(2)+2HCl to MgCl_(2)+2H_(2)O`
`"Number of moles of stomach acid neturalized"=2xx"number of moles of "Mg(OH)_(2)`
`=2xx(1)/(58.33)=0.0343`
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