When a mixture of 10 moles of `SO_(2)` and 16 moles of `O_(2)` were passed over a catalyst, 8 moles of `SO_(3)` were formed at equilibrium. The number of `SO_(2) and O_(2)` remaining unreacted were:

Options

A. 2,12
B. 12,2
C. 3,10
D. 10,3

Answer

A

Explanation

`2SO_(2)(g)+O_(2)(g) Leftrightarrow 2SO_(3)(g)`
`{:(,t=0,10,16,0),(,t_(eq),(10-2x),(16-x),0),(, ,(2x=8), ,x=4):}`
`therefore "Remaining "SO_(2)=10-8=2"mol"`
` "Remaining "O_(2)=16-4=12"mol"`