If 0.5 mole of `BaCl_(2)` are mixed with 0.2 mole of `Na_(3)PO_(4)`,the maximum number of moles. Of `Ba_(3)(PO_(4)_(2))` that can be formed, is

Options

A. 0.7
B. 0.5
C. 0.2
D. 0.1

Answer

D

Explanation

`3BaCl_(2)+2NaPO_(4) to Ba_(3)(PO_(4))_(2)+6NaCl`
`"Number of moles of "Ba(PO_(4))_(2)"formed by "BaCl_(2)=(1)/(3)xx0.5=0.166`
`"Number of moles of "Ba(PO_(4))_(2)"formed by "Na_(3)PO(4)=(1)/(2)xx0.2=0.1`
Thus, `Na_(3)PO_(4)` will be limiting and actual amount of product will be 0.1mole.