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When 10g of 90% pure limestone is heated...

When 10g of 90% pure limestone is heated, the volume of `CO_(2)` (in litre) liberated at STP is:

A

22.4litre

B

2.24litre

C

20.16litre

D

2.016litre

Text Solution

Verified by Experts

The correct Answer is:
D

`"Mass of "CaCO_(3) "in the sample "=10xx(90)/(100)=9g`
`underset(100g)underset(1"mol")(CaCO_(3)(s)) to CaO(s)+underset(22.4L)underset(1"mol")(C_(2)(g))`
`"9gm "CaCO_(3) "will give" ((22.4)/(100)xx9)"litre of "CO_(2), i.e. 2.016"litre of"CO_(2)`
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