Compound (A) contains only carbon and hydrogen. Id decolourises bromine in `C(Cl_(4))` solution and reacts slowly with concentrated `H_(2)SO_(4)`. Compound (A) reacts with HBr to form (B). (B) reacts with NaOH to form ( C). On oxidation ( C) gives hexane-3. Write the structural formulae of (A), (B), (C) and explain the reactions involved.

Explanation

(A) is an alkene as it decolourless bromine in `C(Cl_(4))` and reacts with `H_(2)SO_(4)`.
( C) is a secondary alcohol as it forms hexanone-3 on oxidation. The structure of C) should be
`CH_(3)CH_(2)-underset(OH)underset(|)(CH-CH_(2)CH_(2)CH_(3)` (hexan-3-ol)
(B) on hydrolysis with NaOH gives (C ) thus, (B) should be
`CH_(3)CH_(2)-underset(Br)underset(|)(CH)-CH_(2)CH_(2)CH_(3)` (3-Bromohexane)
(A) on HBr addition gives (B) hence, (A) is
`CH_(3)CH_(2)CH=CHCH_(2)CH_(3)`
Reaction.