a) Compound (A) `C_(8)H_(12)` on oxidation gives an acid (B) `C_(4)H_(6)O_(2)`. One molecule of compound (A) reacts with 3 mole of `H_(2)` in presence of platinum catalyst to give octane. Identify compound (A).

Explanation

The number of carbon atoms `(C_(8))` in (A) is twice the number of carbon atoms `(C_(4))` in acid (B). So 2 mole of acid `C_(4)H_(6)O_(4)` join with each other to give the compound (A).

Since, the cyclopropane ring is highly strained ring, so on catalyst hydrogenation, 3 moleof `H_(2)` are required i.e., one mol for each of cyclopropane ring and one mol for reducing the `(C=C)` bond.
b)
So,2 mole of each of the products `C_(3)` are obtained by oxidation of (A). Two (C=O) groups of two acetone are joned with two (C=O) groups of dicarboxyclic acid and then removing the oxygen atoms and joining the carbon atoms with double bonds gives the structure of compound (A)